2x^2+9x=300

Solution for 2x^2+9x=300 equation:

2x^2+9x=300

We move all terms to the left:

2x^2+9x-(300)=0

a = 2; b = 9; c = -300;
Δ = b2-4ac
Δ = 92-4·2·(-300)
Δ = 2481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{2481}}{2*2}=\frac{-9-\sqrt{2481}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{2481}}{2*2}=\frac{-9+\sqrt{2481}}{4}
$